SOLUTION: Find two consecutive even integers such that three times the smaller is 30 more than twice the larger.

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Question 253557: Find two consecutive even integers such that three times the smaller is 30 more than twice the larger.
Found 2 solutions by richwmiller, Fombitz:
Answer by richwmiller(17219) About Me  (Show Source):
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3n=2*(n+2)+30
n=34
and 36
check
3*34=2*36*30
102=72+30
102=102
ok

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the smaller, B the larger.
B=A+2
.
.
.
3A=2B+30
Substitute from above,
3A=2(A+2)+30
3A=(2A+4)+30
A=34
Then
B=36