SOLUTION: find three consecutive even numbers such that the square of the first number decreased by 3 times the second plus the third number is 22

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Question 253383: find three consecutive even numbers such that the square of the first number decreased by 3 times the second plus the third number is 22
Answer by palanisamy(496) About Me  (Show Source):
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Let the three consecutive even integers be x,x+2 and x+4
Given, the square of the first number decreased by 3 times the second plus the third number is 22
x^2-3(x+2)+(x+4) = 22
x^2-3x-6+x+4 = 22
x^2-2x-24 = 0
(x-6)(x+4) = 0
x = 6 or -4
x cannot be negative.
Therefore x = 6.
So the given numbers are 6,8,10