x = 1st odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Subtract 12 from all three sides
Divide through by 4
The only odd integer x between 8.5 and 10.5 is 9.
So there is just one set:
x = 1st odd integer = 9
x+2 = 2nd odd integer = 11
x+4 = 3rd odd integer = 13
x+6 = 4th odd integer = 15
sum = 9+11+13+15=48
Edwin