Question 253323: find all sets of four consecutive integers whose sum is between 16 and 24 Found 2 solutions by richwmiller, Edwin McCravy:Answer by richwmiller(17219) (Show Source):
x = 1st integer
x+1 = 2nd integer
x+2 = 3rd integer
x+3 = 4th integer
Subtract 6 from all three sides
Divide through by 4
The only two integers x between 2.5 and 4.5 are 3 and 4
So there are two sets:
x = 1st integer = 3
x+1 = 2nd integer = 4
x+2 = 3rd integer = 5
x+3 = 4th integer = 6
sum = 3+4+5+6=18
and
x = 1st integer = 4
x+1 = 2nd integer = 5
x+2 = 3rd integer = 6
x+3 = 4th integer = 7
sum = 4+5+6+7=22
Edwin