SOLUTION: The area of a trapezoid is found using A = 1/2 (b1 + b2)h where b1 is one base, b2 is the second base, and h is the height. Suppose a trapezoid has a base of 5x, another base of 9x

Algebra ->  Surface-area -> SOLUTION: The area of a trapezoid is found using A = 1/2 (b1 + b2)h where b1 is one base, b2 is the second base, and h is the height. Suppose a trapezoid has a base of 5x, another base of 9x      Log On


   

Question 253225: The area of a trapezoid is found using A = 1/2 (b1 + b2)h where b1 is one base, b2 is the second base, and h is the height. Suppose a trapezoid has a base of 5x, another base of 9x, and a height of 8xy. What is the area?
Found 2 solutions by Nikki456, richwmiller:
Answer by Nikki456(9) About Me  (Show Source):
You can put this solution on YOUR website!
You could substitute these values into your formula. A= 1/2 (5x+9x) 8xy. You simplify it and you should get A= 1/2 (14x)8xy. you could further 1/2(14x)8xy could be simplified even further into (7x)8xy. Then your final answer would be 56x%5E2y.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
A = 1/2 (b1 + b2)h
Just plug in the values given
A=1/2(9x+5x)*8xy
A=1/2(14x)+8xy
A=7x+8xy
A=x(7+8y)