SOLUTION: A rectangular box a square base is shown. If the volume of the box is 256 cubic feet and the height of the box is one-half the length of a side of the base, find the height of the

Algebra ->  Volume -> SOLUTION: A rectangular box a square base is shown. If the volume of the box is 256 cubic feet and the height of the box is one-half the length of a side of the base, find the height of the      Log On


   

Question 253098: A rectangular box a square base is shown. If the volume of the box is 256 cubic feet and the height of the box is one-half the length of a side of the base, find the height of the box.
a=2l+2w
256=(1/2)2l+2w
Found 2 solutions by checkley77, richwmiller:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
First you have the wrong area formula.
Area=L*W*H
256=x*x*x/2
256=x^3/2
x^3=256*2
x^3=512
x=cubert512
x=8 ans. for the sides of the square base.
8/2=4 ans. for the height of the box.
Proof:
256=8*8*4
256=256

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Let's get the formulas for a rectangle right.
Perimeter =2L+2W
Area=L*W
Volume=L*W*H
where L=length
W=width
and H=height or depth