SOLUTION: Jason has the same number of red and of blue marbles. He puts them in two jars so that the ratios of the number of red marbles to blue marbles in jar I is 2:5 and in jar II is 9:5.

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Question 253047: Jason has the same number of red and of blue marbles. He puts them in two jars so that the ratios of the number of red marbles to blue marbles in jar I is 2:5 and in jar II is 9:5. If there are 84 marbles in jar I, how many are there in jar II ?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
R=B
JarI
2+5=7=t
r/b=2/5
r/t=2/7
b/t=5/7
b/84=5/7
7b/84=5
b/12=5
b=60
t-b=r
84-60=24
r=24
24 red and 60 blue in JarI
JarII
r/b
9r/5b
r=b
9m+24=5m+60
m=9
m=mulitplier
9*9/9*5
81/45
81+24=105 red
60+45=105 blue
jarI
24red
60 blue
jarII
81 red jarII
45 blue jarII
81+45=126 in jarII answer
9/5
9*9=81
9*5=45
9/5=81/45
total red=105
total blue=105
answer 81 red+45 blue=126 marbles in jarII