Question 253005: jaime is now 35 years older than his son. in 5 years, he will be twice as old as his son. what are their present ages?
Answer by hokies(65)   (Show Source):
You can put this solution on YOUR website! J = S + 35
J+5 = 2*(S+5)
Two equations and two unknowns. Solve this system of equations:
J = 65
S = 30
Another way: If Jaime is 35 years older than his son now, then he will also be 35 years older than his son 5 years from now. If Jaime is twice his son's age 5 years from now, then their ages 5 years from now must be 35 and 70. Therefore, their ages now are 30 and 65.
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