SOLUTION: Hi, I am trying to help my son with this applied math 10 problem and I need some help. A car is travelling at 60 km/h West away from Vancouver. It is 200 km away from Vancouv

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Question 252909: Hi,
I am trying to help my son with this applied math 10 problem and I need some help.
A car is travelling at 60 km/h West away from Vancouver. It is 200 km away from Vancouver after 3 hours. Write an equation which models this situation. Use the equation to determine the distance away from Vancouver after 8 hrs. The teacher wants the question to be answered in this format below.
m = _______________ (x,y) = ( )
Could you help me please?
Thank you and Happy New Year,
Phill

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
There are problems with the givens
If the car is traveling at 60 kmh it will not be 200 miles from Vancouver after 3 hours if the car started at the border of Vancouver.
rt=d
rate *time =distance
rt=d
60*3=180
So it must have started out 20 km away from the border of Vancouver.
but here we have to adapt
Distance =20+60*t
20=b
60=m
where t=time in hours
so after 8 hours
d=20+60*8
i am guessing that the teacher wants something like
y=mx+b
this is the slope intercept form of a linear equation
y=60x+20
where m=60 and b=20
y=distance
and x= time
so we have
after 8 hours
y=60*8+20
I do not understand your
m=_____(x,y)=()
we can solve our equation for m
y=60x+20
y-20=60x
60=(y-20)/x
m=(y-20)/x
60=(y-20)/8
But I don't see the point in that form.