SOLUTION: I think I have submitted this before but I have really been confused. I did some of it but think I did it wrong as the answer doesn't make sense.
An open-top box is to be connec
Algebra ->
Volume
-> SOLUTION: I think I have submitted this before but I have really been confused. I did some of it but think I did it wrong as the answer doesn't make sense.
An open-top box is to be connec
Log On
Question 25283: I think I have submitted this before but I have really been confused. I did some of it but think I did it wrong as the answer doesn't make sense.
An open-top box is to be connected from a 6 by 8 foot rectangular cardboard by cutting out equal squares at each corner and then folding up the flaps. Let x denote the length of each side of the square to be cut out. Find the function V that represents the volume of the box in terms of x.
This is what I got:
6x+8x+x=14x²
x=14
What if anything did I do wrong? Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! An open-top box is to be connected from a 6 by 8 foot rectangular cardboard by cutting out equal squares at each corner and then folding up the flaps. Let x denote the length of each side of the square to be cut out. Find the function V that represents the volume of the box in terms of x.
This is what I got:
6x+8x+x=14x²
x=14
LENGTH OF BOARD=6 FT....WIDTH OF BOARD =8 FT.
IF X LONG SQUARE PIECES ARE CUT AT 4 CORNERS WE SHALL HAVE THE BOX DIMENSIONS AS
HEIGHT =X.....LENGTH = 6-2X.....WIDTH =8-2X
VOLUME = V = L*W*H =X(6-2X)(8-2X)=X(48-28X+4X^2)=48X-28X^2+4X^3