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Question 252704: Solving Linear Systems by Graphs and Tables
Guided Practice:
2. y=3-x
y=x+1
3. y = 1/2 x -3/2
y = 2x-6/4
4. y = x+3/2
y = 2x-3/4
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! Let's take them one at a time:
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2.
(i) y = 3 - x
(ii)y = x + 1
Creating a table of values, we get:
X . . . -2 . . -1 . . . 0 . . . 1 . . . 2
Y(i). . .5 . . . 4 . . . .3 . . . 2 . . . 1
Y(ii) . .-1 . . 0 . . . 1. . . .2 . . . 3
Notice the Y's are equal at 2, when X = 1. You should be able to graph this now.
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3.
(i) y = 1/2 x -3/2
(ii) y = 2x-6/4
Creating a table of values, we get:
X . . . . .. . . -4 . . . . . . .-2 . . . . . . . . . 0 . . . . . . . . 2 . . . .. . . . 4
Y(i). . . . . -7/2 . . . .. . -5/2 . . . . . . . -3/2 . . .. . .-1/2 . . . . . 1/2
Y(ii) . . . .-19/2 . . . . . . -11/2 . . . . . -3/2 . . .. . . .5/2 . . . . . . 13/2
Notice the Y's are equal at -3/2, when X = 0. You should be able to graph this now.
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4.
(i)y = x+3/2
(ii)y = 2x-3/4
Creating a table of values, we get:
X . . . . .. . . 0 . . . . . . .3/4 . . . . . . . . . 6/4 . . . . . . . . 9/4 . . . .. . . . 12/4
Y(i). . . . . 3/2 . . . .. . 9/4 . . . . . . . . . 3 . . . . . . . 15/4 . . . . . . . .9/2
Y(ii) . . . .-3/4 . . . . . . 3/4 . . . . . . 9/4 . . . . . . . . .15/4 . . . . . . . 21/4
Notice the Y's are equal at 15/4, when X = 9/4. You should be able to graph this now.
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