SOLUTION: May rides her bike the same distance that leah walks. may rides her bike 10 km/h faster than leah walks. if it takes may 1 h and leah 3 h to travel that distance, how fast does eac
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Question 252690: May rides her bike the same distance that leah walks. may rides her bike 10 km/h faster than leah walks. if it takes may 1 h and leah 3 h to travel that distance, how fast does each travel? Found 2 solutions by stanbon, richwmiller:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! May rides her bike the same distance that leah walks. may rides her bike 10 km/h faster than leah walks. if it takes may 1 h and leah 3 h to travel that distance, how fast does each travel?
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May DATA:
time = 1 hr. ; rate = x+10 mph ; distance = rt = (x+10)*1 mi
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Leah DATA:
time = 3 hr. ; rate = x mph ; distance = rt = 3x mi
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Equation:
distance = distance
x+10 = 3x
2x = 10
x = 5 mph (Leah's rate)
x+10 = 15 mph (May's rate)
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Cheers,
Stan H.
You can put this solution on YOUR website! rt=d
let x be leah's speed
may's speed is 10+x
(10+x)*1=3x
10+x=3x
10=2x
x=5
x+10=15
so may goes 15 kmh and leah 5
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