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| Question 252614:  Can you help me solve this questions, please?
 The original ferris wheel, designed by George Ferris, was 250 feet in diameter. Making 1 revolution for every 40 seconds, h(t)=125sin(0.157t -pi/2) +125 represents the height h (feet) of a seat on the wheel at any time t (seconds). The ride begins when t = 0. During the first 30 seconds of the ride, at what time is a rider on the ferris wheel exactly 125 feet above the ground?
 and also, help me with:
 approximate the solution to 2cosx+x=0 to the nearest hundredth.
 Hints: it should be in radian mode and there are no () around the x+x
 Thanks so much!!
 Found 2 solutions by  jim_thompson5910, drk:
 Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website!  Start with the given equation. 
 
 
  Plug in   
 
 
  Subtract 125 from both sides. 
 
 
  Combine like terms. 
 
 
  Divide both sides by 125. 
 
 
  Reduce. 
 
 
  Rearrange the equation 
 
 
  Take the arcsine of both sides. 
 
 
  or  Evaluate the arcsine of 0 to get  or  . Don't forget to add in integer multiples of   
 ---------------------------Side Note----------------------
 
 Take note how if
  , then we just get 0 or  . If  , then we get  or  . If we continue this, we can see that we'll hit all of the integer multiples of  . Because of this we can condense the right side to just  . 
 --------------------------------------------------------
 
 
 
  Condense the right side (see side note above). 
 
 
  Add  to both sides. 
 
 
  Combine like terms. 
 
 
  Multiply both sides by  to isolate 't'. 
 
 
  Multiply. 
 
 Now let's plug in some values of 'n'. If n=0, then
   
 If n=1, then
  . However, since we're only worried about the first 30 seconds, this means that  which would exclude the 't' value when  . Any other value of 'n' will generate a 't' value outside the interval   
 =====================================
 Answer:
 
 So the only solution is
  (which is approximate) which means that at about 10.00507 seconds, the rider will be 125 feet above the ground during the first 30 seconds. 
 
 ===========================================================================
 
 # 2
 
 Since the variable we want to solve for in
  is buried in a trig function and is outside the trig function, there is no way to solve for it exactly. 
 
 So we have to use a graphing calculator to approximate the roots of
  . Graphing the given expression, we get 
 
   
 Graph of
   
 
 Now use the graphing calculator's root/zero function to find the approximate root of
  which rounds to  to the nearest hundredth. 
 
 So the answer is
  Answer by drk(1908)
      (Show Source): 
You can put this solution on YOUR website! QUESTION #1: We have the formula 
  we want the h(t) = 125. So,
 125 =125sin(0.157t -pi/2) + 125
 0 = sin(0.157t -pi/2)
 sin^-1(0) = (0.157t -pi/2)
 {0, PI} = (0.157t -pi/2)
 At this point we split and solve:
 0 = (0.157t -pi/2)
 pi/2 = .157t
 *
 t = 10 seconds
 pi = (0.157t -pi/2)
 3pi/2 = .157t
 t = 30 seconds.
 ----
 QUESTION #2: approximate the solution to 2cosx+x=0 to the nearest hundredth.
 2cosx + x = 0
 2cosx = -x
 cosx = -(1/2)x
 I don't see any solutions.
 
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