SOLUTION: Can you help me solve this questions, please? The original ferris wheel, designed by George Ferris, was 250 feet in diameter. Making 1 revolution for every 40 seconds, h(t)=125s

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Question 252614: Can you help me solve this questions, please?
The original ferris wheel, designed by George Ferris, was 250 feet in diameter. Making 1 revolution for every 40 seconds, h(t)=125sin(0.157t -pi/2) +125 represents the height h (feet) of a seat on the wheel at any time t (seconds). The ride begins when t = 0. During the first 30 seconds of the ride, at what time is a rider on the ferris wheel exactly 125 feet above the ground?
and also, help me with:
approximate the solution to 2cosx+x=0 to the nearest hundredth.
Hints: it should be in radian mode and there are no () around the x+x
Thanks so much!!

Found 2 solutions by jim_thompson5910, drk:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
h%28t%29=125sin%280.157t+-pi%2F2%29%2B125 Start with the given equation.


125=125sin%280.157t+-pi%2F2%29%2B125 Plug in h%28t%29=125


125-125=125sin%280.157t+-pi%2F2%29 Subtract 125 from both sides.


0=125sin%280.157t+-pi%2F2%29 Combine like terms.


0%2F125=sin%280.157t+-pi%2F2%29 Divide both sides by 125.


0=sin%280.157t+-pi%2F2%29 Reduce.


sin%280.157t+-pi%2F2%29=0 Rearrange the equation


0.157t-pi%2F2=arcsin%280%29 Take the arcsine of both sides.


0.157t-pi%2F2=0%2B2pi%2An or 0.157t-pi%2F2=pi%2B2pi%2An Evaluate the arcsine of 0 to get 0 or pi. Don't forget to add in integer multiples of 2pi

---------------------------Side Note----------------------

Take note how if n=0, then we just get 0 or pi. If n=1, then we get 2pi or 3pi. If we continue this, we can see that we'll hit all of the integer multiples of pi. Because of this we can condense the right side to just pi%2An.

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0.157t-pi%2F2=pi%2An Condense the right side (see side note above).


0.157t=pi%2An%2Bpi%2F2 Add pi%2F2 to both sides.


0.157t=%282pi%2An%2Bpi%29%2F2 Combine like terms.


t=%28%282pi%2An%2Bpi%29%2F2%29%281%2F0.157%29 Multiply both sides by 1%2F0.157 to isolate 't'.


t=%282pi%2An%2Bpi%29%2F0.314 Multiply.


Now let's plug in some values of 'n'. If n=0, then t=%282pi%2A0%2Bpi%29%2F0.314=pi%2F0.314=10.00507

If n=1, then t=%282pi%2A1%2Bpi%29%2F0.314=3pi%2F0.314=30.01522. However, since we're only worried about the first 30 seconds, this means that 0%3C=t%3C=30 which would exclude the 't' value when n=1. Any other value of 'n' will generate a 't' value outside the interval 0%3C=t%3C=30

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Answer:

So the only solution is t=10.00507 (which is approximate) which means that at about 10.00507 seconds, the rider will be 125 feet above the ground during the first 30 seconds.


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# 2

Since the variable we want to solve for in 2%2Acos%28x%29%2Bx=0 is buried in a trig function and is outside the trig function, there is no way to solve for it exactly.


So we have to use a graphing calculator to approximate the roots of 2%2Acos%28x%29%2Bx. Graphing the given expression, we get



Graph of y=2%2Acos%28x%29%2Bx


Now use the graphing calculator's root/zero function to find the approximate root of x=-1.029866529 which rounds to x=-1.03 to the nearest hundredth.


So the answer is x=-1.03

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
QUESTION #1: We have the formula
h%28t%29=125sin%280.157t+-pi%2F2%29+%2B125
we want the h(t) = 125. So,
125 =125sin(0.157t -pi/2) + 125
0 = sin(0.157t -pi/2)
sin^-1(0) = (0.157t -pi/2)
{0, PI} = (0.157t -pi/2)
At this point we split and solve:
0 = (0.157t -pi/2)
pi/2 = .157t
*
t = 10 seconds
pi = (0.157t -pi/2)
3pi/2 = .157t
t = 30 seconds.
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QUESTION #2: approximate the solution to 2cosx+x=0 to the nearest hundredth.
2cosx + x = 0
2cosx = -x
cosx = -(1/2)x
I don't see any solutions.