SOLUTION: I need help with this and i hope this is the right place to put it http://www2.edmastery.com/li/itemAssets/nnds

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Question 252407: I need help with this and i hope this is the right place to put it
http://www2.edmastery.com/li/itemAssets/nnds_li%20-%20production%5Cdmeyer%5C30.bmp
Found 2 solutions by MRperkins, ankor@dixie-net.com:
Answer by MRperkins(300) (Show Source):
You can put this solution on YOUR website!
You can use basic test taking techniques to find your answer if you know that perpendicular lines have opposite reciprocal slopes. This means that if the lines are perpendicular and one line has a slope of -5/3, then the line perpendicular to that line will have a slope of 3/5. You flip the number over and give it the opposite sign (positive or negative).
There is only one answer in your problem that does this. However, you can go further and put the point (-5,7) into the equation with the new slope and you will get your y-intercept value as well.
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Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Write an equation in slope-intercept form of line that passes thru -5,7
And is perpendicular to the graph of y = x - 1
:
Find the slope of the perpendicular line (m2):
m1 * m2 = -1
:
* m2 = -1
m2 = -1 *
m2 =
:
use the point/intercept formula: y - y1 = m(x - x1)
where
m =
x1 = -5
y1 = 7
:
y - 7 = (x - (-5))
y - 7 = (x + 5)
y - 7 = x + (*5)
y - 7 = x +
y = x + + 7
y = x + +
y = x +
which is
y = 2x + 20

SOLUTION: I need help with this and i hope this is the right place to put it http://www2.edmastery.com/li/itemAssets/nnds_li%20-%20production%5Cdmeyer%5C30.bmp