SOLUTION: Factor completely: (5x^2 + 14x + 13)^2 - 16(x^2 + x - 2)^2
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Algebra: Distributive, associative, commutative properties, FOIL
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Question 252301
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Factor completely: (5x^2 + 14x + 13)^2 - 16(x^2 + x - 2)^2
Answer by
drk(1908)
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This is a difference of squares:
the tricky part is to notice that 16 = 4^2. So the second term is really 4^2(X^2+x-2)^2
combine like terms within each large [stuff]
continue factoring