SOLUTION: Consider the operation # such that a # b = –3a + b^2. Find (–2 # 3) # 6. A. –9 B. 9 C. 15 D. 27 E. 45

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Consider the operation # such that a # b = –3a + b^2. Find (–2 # 3) # 6. A. –9 B. 9 C. 15 D. 27 E. 45      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 252236: Consider the operation # such that a # b = –3a + b^2. Find (–2 # 3) # 6.
A. –9 B. 9 C. 15 D. 27 E. 45
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
a # b means -3a + b^2

find (-2 # 3) # 6

you would first solve what is in the parentheses.

in the equation a # b = (-3a + b^2), you would replace a with -2 and b with 3 to get:

-3*-2 + 3^2 = 6 + 9 = 15.

your equation (-2 # 3) # 6 becomes:

15 # 6.

in the equation a # b = (-3a + b^2), you would replace a with 15 and b with 6 to get:

-3*15 + 6^2 = -45 + 36 = -9.

your answer would be -9 which would be selection A.