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| Question 252139:  A company installs 5000 light bulbs, each with an average life of 500 hours, standard deviation of 100 hours, and distribution approximated by a normal curve.  Find the percentage of bulbs that can be expected to last the period between:
 a) 290 hours and 500 hours.
 b) 540 hours and 780 hours.
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! A company installs 5000 light bulbs, each with an average life of 500 hours, standard deviation of 100 hours, and distribution approximated by a normal curve. Find the percentage of bulbs that can be expected to last the period between: a) 290 hours and 500 hours.
 Find the fraction of population between those limits.
 z(290) = (290-500)/100 = -2.1
 z(500) = (500-500)/100 = 0
 normalcdf(-2.1,0) = 0.4821
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 %age = 0.4821*5000 = 2410.67
 Rounding down = 2410
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 b) 540 hours and 780 hours.
 z(540) = (540-500)/100 = 0.4
 z(780) = (780-500)/100 = 2.8
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 P(540 < x < 780) = P(0.4 < z < 2.8) = 0.3420..
 %age = 0.3420*5000 = 1719
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 Cheers,
 Stan H.
 
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