SOLUTION: Fernando’s motorboat can travel 30 mi/hr in still water.
If the boat can travel 9 miles downstream in the same time it takes to travel 1 miles upstream, what is the rate of the r
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-> SOLUTION: Fernando’s motorboat can travel 30 mi/hr in still water.
If the boat can travel 9 miles downstream in the same time it takes to travel 1 miles upstream, what is the rate of the r
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Question 252133: Fernando’s motorboat can travel 30 mi/hr in still water.
If the boat can travel 9 miles downstream in the same time it takes to travel 1 miles upstream, what is the rate of the river’s current? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! (30+x)*t=9
(30-x)*t=1
t=1/54 time
x=24 rate of current
another way of solving
t=9/(30+x)
t=1/(30-x)
9/(30+x)=1/(30-x)
x=24= rate of current
check
9/(30+24)=1/(30-24)
9/54=1/6
1/6=1/6
ok
