Question 252073: Find three of the consecutive integer whose sum is equal to six. List answers from least to greatest?
Found 2 solutions by drk, MRperkins: Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! Let n be the first integer, n+1 be the second, and n+2 be the third integer. The sum of these three is n+n+1+n+2 = 3n + 3. This sum must equal 6. So, we have
n+n+1+n+2 = 6
3n + 3 = 6
3n = 3
n = 1
We have our three consecutive integers in order as 1, 2, 3.
Answer by MRperkins(300) (Show Source):
You can put this solution on YOUR website! You can either think about this and try a couple of numbers OR you can learn how to do this algebraically.
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consecutive numbers mean that you have a number, then you have the next number, and the next number, and so on...
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Any number can be represented by a letter. Since we are talking about numbers, and numbers starts with the letter "n", lets call our number n.
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In order to have 3 consecutive numbers where n is one of the numbers, we need the number after n. We can add 1 to n to get the number after n. Therefore, the number after n is represented by n+1.
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We can do the same thing to find the number after n+1. We simply add 1 to find the next number, so the 3rd consecutive number is 1 more than n+1 or simply n+2.
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We know that the first number plus the second number plus the third number is equal to 6. So let's write our numbers just like what we just said. n+(n+1)+(n+2)=6
We can drop the parenthesis in this case because everything is being added and there is no multiplication or exponents. So we have
n+n+1+n+2=6
3n+3=6
3n=3
n=1
now we plug this number in for n and find out our 3 numbers.
remember, the first number was n so it is 1
the second number was n+1, so it is 2
the third number was n+2, so it is 3.
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I hope this helps and clears things up for you. This is actually a problem that can be guessed in your head, but if you learn the fundamentals of what I just explained, then you will be able to take on the more difficult problems as well.
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Respectfully,
Justin
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