Question 252046: How do I graph the quadratic functionof y= -x to the 2nd power minus 4x plus 2? And how do I Label the vertex and axis of symmetry?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! How do I graph the quadratic functionof y= -x to the 2nd power minus 4x plus 2? And how do I Label the vertex and axis of symmetry?
------
y = -x^2-4x+2
a = -1 ; b = -4 ; c = 2
----------------------------
Vertex occurs where x = -b/2a = 4/(2*-1) = -2
f(-2) = -(-2)^2-4(-2)+2 = 6
--
Plot the vertex at (-2,6)
--------------
y-intercept = f(0) = 2
Plot the point (0,2)
--------------
Since "a" is negative the parabola opens downward and has a max at (-2,6)
--------------
With that information you should be able to sketch the graph.
=============================
Cheers,
Stan H.
|
|
|
