SOLUTION: (5+2i)-(4-7i) and (4-7i)-(5+2i)

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: (5+2i)-(4-7i) and (4-7i)-(5+2i)      Log On


   



Question 252021: (5+2i)-(4-7i) and (4-7i)-(5+2i)
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Did this as #252020
But if you are adding the two groups together you get zero
(5+2i)-(4-7i) and (4-7i)-(5+2i)