Question 251604:  Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Transform the second expression into the equivalent logarithmic equation; and evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1.
 
y= (5/2)^x   
x= (5/2)^y 
 Answer by drk(1908)      (Show Source): 
You can  put this solution on YOUR website! Here is my answer based on my understanding of the instructions: 
Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. 
  
(X,Y): (-3, 8/125), (-2, 4/25) (-1, 2/5) (0,1) (1,5/2) (2,25/4) (3,125/8)
 
Transform the second expression into the equivalent logarithmic equation 
  
log(x) = ylog(5/2) 
y = log(x) / log(5/2)
 
evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1.
 
(X,Y): (.25, -1.513) (.5, -.7564) (.75, -.3140) (1, 0) (2, .7565) (3, 1.990) (4, 1.5129) 
  | 
 
  
 
 |   
 
 |