SOLUTION: Can someone help me with these two questions? Thanks 1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Transform the s

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Can someone help me with these two questions? Thanks 1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Transform the s      Log On


   



Question 251578: Can someone help me with these two questions? Thanks
1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Transform the second expression into the equivalent logarithmic equation; and evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Use the resulting ordered pairs to plot the graph of each function; y=2^x, x=2^y

8. Evaluate the exponential function for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph; State the domain and the range of the function.
f(x) = e^-x -1

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
first equatioon is y = 2^x

values of x are:

-3
-2
-1
0
1
2
3

when x = -3, 2^x = 2^(-3) = 1/2^3 = 1/8

when x = -2, 2^x = 2^(-2) = 1/2^2 = 1/4

when x = -1, 2^x = 2^(-1) = 1/2^1 = 1/2

when x = 0, 2^x = 2^0 = 1

when x = 1, 2^x = 2^1 = 2

when x = 2, 2^x = 2^2 = 4

when x = 3, 2^x = 2^3 = 8

graph of the equation looks like this:

graph%28600%2C600%2C-5%2C5%2C-1%2C10%2C2%5Ex%29

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x = 2^y if and only if log%282%2Cx%29+=+y

this is the same as y+=+log%282%2Cx%29

values for x are:

.1
.4
.7
1
2
3
4

when x = .1, y = log%282%2Cx%29 = log%282%2C.1%29 = log%2810%2C.1%29%2Flog%2810%2C2%29+=+-3.321928095

when x = .4, y = log%282%2Cx%29 = log%282%2C.4%29 = log%2810%2C.4%29%2Flog%2810%2C2%29+=+-1.321928095

when x = .7, y = log%282%2Cx%29 = log%282%2C.7%29 = log%2810%2C.7%29%2Flog%2810%2C2%29+=+-.0514573173

when x = 1, y = log%282%2Cx%29 = log%282%2C1%29 = log%2810%2C1%29%2Flog%2810%2C2%29+=+0

when x = 2, y = log%282%2Cx%29 = log%282%2C2%29 = log%2810%2C2%29%2Flog%2810%2C2%29+=+1

when x = 3, y = log%282%2Cx%29 = log%282%2C3%29 = log%2810%2C3%29%2Flog%2810%2C2%29+=+1.584962501

when x = 4, y = log%282%2Cx%29 = log%282%2C4%29 = log%2810%2C4%29%2Flog%2810%2C2%29+=+2

graph of this equation looks like this:

graph%28600%2C600%2C-1%2C5%2C-1%2C5%2Clog%282%2Cx%29%29

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graph of both equations together looks like this:

graph%28600%2C600%2C-5%2C10%2C-5%2C10%2C2%5Ex%2Clog%282%2Cx%29%2Cx%29

since the equation of y = 2^x is the inverse of equation x = 2^y, these equations are symmetric about the line y = x as shown in the graph.

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8. Evaluate the exponential function for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph; State the domain and the range of the function.
f(x) = e^-x -1

equation is e%5E%28-x%29+-+1

values of x are:

-3,-2,-1,0,1,2,3

when x = -3, equation becomes e%5E%28-%28-3%29%29+-+1 = e%5E%283%29-1 = 19.08553692

when x = -2, equation becomes e%5E%28-%28-2%29%29+-+1 = e%5E%282%29-1 = 6.389056099

when x = -1, equation becomes e%5E%28-%28-1%29%29+-+1 = e%5E%281%29-1 = 1.718281828

when x = 0, equation becomes e%5E%280%29+-+1 = 0

when x = 1, equation becomes e%5E%28-1%29 = -.632120559

when x = 2, equation becomes e%5E%28-2%29-1 = -.864664717

when x = 3, equation becomes e%5E%28-3%29-1 = -.950212932

graph of equation looks like this:

graph%28600%2C600%2C-5%2C15%2C-3%2C25%2Ce%5E%28-x%29-1%29

the domain of the equation is all real values of x.

the range of the equation is all real values of y > -1

x will never be less then or equal to -1.