Question 251496: 1.Solve the problem.
Given log b 3 = 3.6887 and log b 7 = 1.4873.
Find logb 3/7
2.Express as a sum, difference, and product of logarithms, without using exponents.
log18 7√x/y
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1.Solve the problem.
Given log b 3 = 3.6887 and log b 7 = 1.4873.
Find logb(3/7) = logb(3)-logb(7) = 3.6887 - 1.4873
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2.Express as a sum, difference, and product of logarithms, without using exponents.
log18 7√x/y
= log18(7)+log18(sqrt(x) - log18(sqrt(y)
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= log18(7) + (1/2)log18(x) - (1/2)log18(y)
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Cheers,
Stan H.
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