Question 251496:   1.Solve the problem.
 
Given log b 3 = 3.6887 and log b 7 = 1.4873. 
Find logb 3/7 
2.Express as a sum, difference, and product of logarithms, without using exponents.
 
log18  7√x/y 
 Answer by stanbon(75887)      (Show Source): 
You can  put this solution on YOUR website! 1.Solve the problem.  
Given log b 3 = 3.6887 and log b 7 = 1.4873. 
Find logb(3/7) = logb(3)-logb(7) = 3.6887 - 1.4873 
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2.Express as a sum, difference, and product of logarithms, without using exponents.  
log18 7√x/y 
= log18(7)+log18(sqrt(x) - log18(sqrt(y) 
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= log18(7) + (1/2)log18(x) - (1/2)log18(y) 
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Cheers, 
Stan H.
 
 
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