SOLUTION: Given two similar triangles, the area of the larger triangle is sixteen times the area of the smaller triangle. Find the ratio of the perimeter of the larger triangle to the perime
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Question 251484: Given two similar triangles, the area of the larger triangle is sixteen times the area of the smaller triangle. Find the ratio of the perimeter of the larger triangle to the perimeter of the smaller triangle . Answer by rfadrogane(214) (Show Source):
You can put this solution on YOUR website! Since its a similar triangle;
so, let A1 = the area of the larger triangle
A2 = the area of the smaller triangle
P1 = the perimeter of the larger triangle
P2 = the perimeter of the smaller triangle
by ratio & proportion:
A1 = 16*A2 ----(1)
(A1/A2) = (P1/P2)^2 ----(2)
substitute (1) into (2)
[(16*A2)/A2] = (P1/P2)^2
taking the sqrt. on both sides;
4P2 = P1
thus, the ratio is:
4:1 --- answer
