SOLUTION: find 3 cinsecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two.

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Question 251384: find 3 cinsecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two.
Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
4x-7=(x+1+x+2)
4x-7=(2x+3)
2x = 10
x=5
So the numbers are 5,6,& 7.