SOLUTION: solve for x: x^3/2(to the 3 over 2) - 27=0 ___________ __ 4^x=79 ___________ __ 9^x+2=27^x ___________ ___________ ___________ ___________ ______ write the logarit

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: solve for x: x^3/2(to the 3 over 2) - 27=0 ___________ __ 4^x=79 ___________ __ 9^x+2=27^x ___________ ___________ ___________ ___________ ______ write the logarit      Log On


   

Question 251057: solve for x:
x^3/2(to the 3 over 2) - 27=0
______________
4^x=79
______________
9^x+2=27^x
______________________________________________________
write the logarithmc equations for the following
A = s^2 /4(s to the 2 over 4) sqrt3
________________
R = sqrt3V/mH (R equals the squareroot of 3V over mH)
Found 2 solutions by richwmiller, JimboP1977:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
You have too many questions qrouped together.
Resubmit individually
x^3/2 - 27=0
x^(2/3)=27
raise both sides to 2/3
x^(3/2*2/3)=27^(2/3)
x^1=27^(2/3)
27(2/3)=
27(1/3)=3
then 3^2=9

Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E%283%2F2%29-+27=0
x%5E%283%2F2%29=27
%28x%5E%283%2F2%29%29%5E%282%2F3%29=+27%5E%282%2F3%29%0D%0A%7B%7B%7Bx+=+27%5E%282%2F3%29
x=+3%2A27%5E%281%2F3%29
x=3%2A3=9
¬
4%5Ex=79
log%28base10%29+4%5Ex+=+log%28base10%2979
x%2Alog%28base10%294=+log%28base10%2979
x=log%28base10%2979%2Flog%28base10%294
x=+3.1518 4dp.
¬
9%5E%28x%2B2%29=27%5Ex lets get the bases to be 3.
%283%5E2%29%5E%28x%2B2%29=+%283%5E3%29%5Ex
3%5E%282x%2B4%29=3%5E%283x%29
2x%2B4=3x
x=4
Now you try the rest...