SOLUTION: How many real number solutions exist for the equation Y=x^2+8x+16

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Question 251049: How many real number solutions exist for the equation
Y=x^2+8x+16
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
A real number "solution" is a zero of the given eqaution.
0+=+x%5E2+%2B8x+%2B+16
0+=+%28x%2B4%29%28x%2B4%29
So the real solutions are -4 and -4. There is double root at x=-4. So when you graph this equation, it will 'just touch' the x axis at the point (-4,0)
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2%2B8x%2B16%29