SOLUTION: I am asking this question to compare it with another question: "The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 10
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: I am asking this question to compare it with another question: "The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 10
Log On
Question 250838: I am asking this question to compare it with another question: "The length of a rectangle is 6 cm less than twice its width. Find the dimensions of the rectangle if its area is 108 cm (squared)." Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is 6 cm less than twice its width . . . Since you read width last, it gets the variable first. So, Width = W and length = 2W - 6.
A = LW
108 = (2W-6)*(W)
108 = 2W^2 - 6W
2W^2 - 6W - 108 = 0
divide all by 2.
W^2 - 3W - 54 = 0
(W-9)(W+6) = 0
W = 9 cm
W = -6 cm. This answer you cannot use.
If W = 9cm, then L = 12 cm.
(