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Question 250717: Two machines fill cereal boxes at the same rate. After the two machines work together for 4 hours, one machine breaks down. The second machine requires 26 more hours to finish filling the boxes. How long would it have taken one of the machines, working alone, to fill the boxes? (rate x time = work completed)
(the work needs to be show using FRACTIONS)
Answer by drk(1908)   (Show Source):
You can put this solution on YOUR website! This is what I call job / time. Here is the formula:
J1/T1 * (together time) + J2/T2 * (together time) = total number of jobs.
J1 is firs persons number of jobs
T1 is first persons time to do the jobs.
Two machines fill cereal box. So, J1 = J2 = 1; B total cereal boxes.
T1 = T2; same rate.
At this pint we have the following equation:
(1/t)(4) + (1/t)(4) + (1/t)(26) = B.
We have to add the alone time of the second machine after the first breaks down. We don't know how many total boxes were to be filled.
Continuing
8/t + 26/t = B
34 = Bt
t = 34/B
This gives you the time to fill B boxes.
Hope this helps.
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