Question 250664: p(odd number and tails)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! p(odd number and tails)
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I'm going to assume you roll a die and you flip a
coin and you want the p(odd on the die and tails on the coin).
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The events are independent, so
P(odd AND tail) = P(odd)*P(tail) = (3/6)(1/2) = 1/4
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Cheers,
Stan H.
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