SOLUTION: factoring polynomials completely p^2 - 2p - 63

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Question 250592: factoring polynomials completely

p^2 - 2p - 63
Found 2 solutions by manglu, richwmiller:
Answer by manglu(4) About Me  (Show Source):
You can put this solution on YOUR website!
chill question
factorise
p^2 - 9p + 7p -63=0
=> p(p-9) + 7(p-9)=0
=> (p+7)(p-9)=0
=> p=-7,9

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
what are factors of 63
63,1
31,3
9,7
which factors have a difference of 2
we need negative two so the bigger factor should be negative
let me know how you do