SOLUTION: In 1880, a man bought some apples at 2 apples for 3 cents and bought the same number of apples at 2 apples for 5 cents. He sold all of the apples at 3 apples for 7 cents. For eac

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: In 1880, a man bought some apples at 2 apples for 3 cents and bought the same number of apples at 2 apples for 5 cents. He sold all of the apples at 3 apples for 7 cents. For eac      Log On