SOLUTION: {{{220y+60y^2-225}}} Factor completely. show steps. if polynomial is prime, state this. I tried to do this but i don't understand how its done. My first attempt I thought it wa

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: {{{220y+60y^2-225}}} Factor completely. show steps. if polynomial is prime, state this. I tried to do this but i don't understand how its done. My first attempt I thought it wa      Log On


   



Question 250391: 220y%2B60y%5E2-225
Factor completely. show steps. if polynomial is prime, state this.
I tried to do this but i don't understand how its done. My first attempt I thought it was prime but my teacher said it was wrong and it could be factored. Could you please help?

Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
220y%2B60y%5E2-225 Start with the given expression.


60y%5E2%2B220y-225 Rearrange the terms.


60y%5E2%2B220y-225 Start with the given expression.


5%2812y%5E2%2B44y-45%29 Factor out the GCF 5.


Now let's try to factor the inner expression 12y%5E2%2B44y-45


---------------------------------------------------------------


Looking at the expression 12y%5E2%2B44y-45, we can see that the first coefficient is 12, the second coefficient is 44, and the last term is -45.


Now multiply the first coefficient 12 by the last term -45 to get %2812%29%28-45%29=-540.


Now the question is: what two whole numbers multiply to -540 (the previous product) and add to the second coefficient 44?


To find these two numbers, we need to list all of the factors of -540 (the previous product).


Factors of -540:
1,2,3,4,5,6,9,10,12,15,18,20,27,30,36,45,54,60,90,108,135,180,270,540
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-27,-30,-36,-45,-54,-60,-90,-108,-135,-180,-270,-540


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -540.
1*(-540) = -540
2*(-270) = -540
3*(-180) = -540
4*(-135) = -540
5*(-108) = -540
6*(-90) = -540
9*(-60) = -540
10*(-54) = -540
12*(-45) = -540
15*(-36) = -540
18*(-30) = -540
20*(-27) = -540
(-1)*(540) = -540
(-2)*(270) = -540
(-3)*(180) = -540
(-4)*(135) = -540
(-5)*(108) = -540
(-6)*(90) = -540
(-9)*(60) = -540
(-10)*(54) = -540
(-12)*(45) = -540
(-15)*(36) = -540
(-18)*(30) = -540
(-20)*(27) = -540

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 44:


First NumberSecond NumberSum
1-5401+(-540)=-539
2-2702+(-270)=-268
3-1803+(-180)=-177
4-1354+(-135)=-131
5-1085+(-108)=-103
6-906+(-90)=-84
9-609+(-60)=-51
10-5410+(-54)=-44
12-4512+(-45)=-33
15-3615+(-36)=-21
18-3018+(-30)=-12
20-2720+(-27)=-7
-1540-1+540=539
-2270-2+270=268
-3180-3+180=177
-4135-4+135=131
-5108-5+108=103
-690-6+90=84
-960-9+60=51
-1054-10+54=44
-1245-12+45=33
-1536-15+36=21
-1830-18+30=12
-2027-20+27=7



From the table, we can see that the two numbers -10 and 54 add to 44 (the middle coefficient).


So the two numbers -10 and 54 both multiply to -540 and add to 44


Now replace the middle term 44y with -10y%2B54y. Remember, -10 and 54 add to 44. So this shows us that -10y%2B54y=44y.


12y%5E2%2Bhighlight%28-10y%2B54y%29-45 Replace the second term 44y with -10y%2B54y.


%2812y%5E2-10y%29%2B%2854y-45%29 Group the terms into two pairs.


2y%286y-5%29%2B%2854y-45%29 Factor out the GCF 2y from the first group.


2y%286y-5%29%2B9%286y-5%29 Factor out 9 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282y%2B9%29%286y-5%29 Combine like terms. Or factor out the common term 6y-5


--------------------------------------------------


So 5%2812y%5E2%2B44y-45%29 then factors further to 5%282y%2B9%29%286y-5%29


===============================================================


Answer:


So 220y%2B60y%5E2-225 completely factors to 5%282y%2B9%29%286y-5%29.


In other words, 220y%2B60y%5E2-225=5%282y%2B9%29%286y-5%29.


Note: you can check the answer by expanding 5%282y%2B9%29%286y-5%29 to get 220y%2B60y%5E2-225 or by graphing the original expression and the answer (the two graphs should be identical).

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
220y%2B60y%5E2-225
The factor of 5 is fairly obvious.
= 5%2A%2844y%2B12y%5E2-45%29
Put it in descending order
= 5%2A%2812y%5E2+%2B+44y+-+45%29
Now it gets harder. Since the -45 is negative, the 2 signs are different.
12 can be 1*12, 2*6 or 3*4
45 can be 1*45, 3*15 or 5*9
It's a trial and error thing to find a combination that gives +44y
(3y + ??)*(4y + ??)
(3y + 5)*(4y - 9) no good
(3y + 3)*(4y - 15) no good
(3y + 1)*(4y - 45) no good
(2y + 5)*(6y - 9) no good
(2y + 9)*(6y - 5) works
--> 5(2y+9)*(6y-5)
-------------------
Do you know the quadratic equation? That's a better way to do these.