Question 250338: John flies from georgia to california. it takes him 5.6 hours to travel 2100 miles against the head wind. at thesame time debby flies form california to georgia. her plane travels with the same average airspeed but her flight only take 4.8 hours. find the windspeed and write a system and solve to find airspeed
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
2,100=R*5.6
R=2,100/5.6
R=375 MPH. AGAINST THE WIND
2,100=R*4.8
R=2,100/4.8
R=437.5 MPH. WITH THE WIND.
(437.5-375)/2=62.5/2=31.25 MPH FOR THE WIND.
PROOF:
437.5-31.25=406.25 MPH FOR THE PLANE IN STILL AIR.
375+31.25=406.25 DITTO.
|
|
|