Question 250156: 47. Pharmacology In placebo-controlled trials of ProzacŪ, a
drug that is prescribed to fight depression, 23% of the
patients who were taking the drug experienced nausea,whereas 10% of the patients who were taking the placebo experienced nausea.*
a. If 50 patients who are taking ProzacŪ are selected, what
is the probability that 10 or more will experience nausea?
b. Of the 50 patients in part a, what is the expected number
of patients who will experience nausea?
c. If a second group of 50 patients receives a placebo,
what is the probability that 10 or fewer will experience
nausea?
d. If a patient from a study of 1000 people, who are equally
divided into two groups (those taking a placebo and
those taking ProzacŪ), is experiencing nausea, what is
the probability that he/she is taking ProzacŪ?
e. Since .23 is more than twice as large as .10, do you think
that people who take ProzacŪ are more likely to experience
nausea than those who take a placebo? Explain.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Pharmacology In placebo-controlled trials of ProzacŪ, a
drug that is prescribed to fight depression, 23% of the
patients who were taking the drug experienced nausea,whereas 10% of the patients who were taking the placebo experienced nausea.*
a. If 50 patients who are taking ProzacŪ are selected, what
is the probability that 10 or more will experience nausea?
--
It's binomial with n=50 , p = 0.23 , 10 <= x <= 50
Prob = 1 - binomcdf(50, 0.23, 9) = 0.7436
------------------------------------------------------------------
b. Of the 50 patients in part a, what is the expected number
of patients who will experience nausea?
np = 50*0.23
---------------------
c. If a second group of 50 patients receives a placebo,
what is the probability that 10 or fewer will experience
nausea?
binomcdf(50,0.10,10)= 0.9906
---------------------
d. If a patient from a study of 1000 people, who are equally
divided into two groups (those taking a placebo and
those taking ProzacŪ), is experiencing nausea, what is
the probability that he/she is taking ProzacŪ?
P(Prozac|nausea) = P(Prozac and nausea)/P(nausea)
= (0.23)/[(P(nausea|Prozac) + P(nausea|placebo)] = 0.23/(0.23 + 0.10)
= 0.23/0.33 = 0.6970
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e. Since .23 is more than twice as large as .10, do you think
that people who take ProzacŪ are more likely to experience
nausea than those who take a placebo? Explain.
I'll leave that to you.
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Cheers,
stan H.
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