SOLUTION: I need to graph this equation using the slope and the y-intercept y=8/3x+6 Can someone help me solve the graph this? Thanks so much

Algebra ->  Linear-equations -> SOLUTION: I need to graph this equation using the slope and the y-intercept y=8/3x+6 Can someone help me solve the graph this? Thanks so much      Log On


   



Question 250059: I need to graph this equation using the slope and the y-intercept
y=8/3x+6
Can someone help me solve the graph this? Thanks so much

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
y=%288%2F3%29x%2B6
When x=0, y=6
Plot the point (0,6).

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Now use the slope and starting at (0,6), when you move 3 units in positive x you move 8 units in positive y.
x=3, y=6+8=14
Plot the point (3,14).

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Again starting at (0,6), when you move 3 units in negative x you move 8 units in negative y.
x=-3, y=6-8=-2
Plot the point (-3,-2).

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Now connect the points with a line,