SOLUTION: A contractor needs 63 square feet of brick to construct a rectangular walkway. The length of the walkway is 2 feet more than the width. What is the perimeter of the walkway

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Question 249858: A contractor needs 63 square feet of brick to construct a rectangular walkway. The length of the walkway is 2 feet more than the width. What is the perimeter of the walkway
Found 2 solutions by mathhub, stanbon:
Answer by mathhub(11) (Show Source):
You can put this solution on YOUR website!
Let the width be x
So length = x + 2
Thus area = x*(x+2)
Given Area = 63
=> x(x+2) = 63
=> x^2 + 2x - 63 = 0
=> x^2 + 9x - 7x -63 = 0
=> x(x+9) -7(x + 9) = 0
=>(x-7)(x+9) = 0
=> x = 7 or x = 9
Thus the width of the walkway is 7 and the length is 9. So the perimeter is
2*(7 + 9)
=2*16
=32

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A contractor needs 63 square feet of brick to construct a rectangular walkway. The length of the walkway is 2 feet more than the width. What is the perimeter of the walkway
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Let the width be "x"; length = "x+2".
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Area = x(x+2) = 63
x^2 + 2x - 63 = 0
(x+9)(x-7) = 0
Positive solution:
x = 7 ft. (width)
x+2 = 9 ft. (length)
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Perimeter = 2(length + width)
P = 2(9+7) = 2(16)
P = 32 ft.
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Cheers,
Stan H.