SOLUTION: A pharmacist uses 5 seperate weights. 1G, 2G,4G,8G,16G. If the pharmacist can combine these weights to create new weights, how many different weights are possible?

Algebra ->  Permutations -> SOLUTION: A pharmacist uses 5 seperate weights. 1G, 2G,4G,8G,16G. If the pharmacist can combine these weights to create new weights, how many different weights are possible?       Log On


   



Question 249766: A pharmacist uses 5 seperate weights. 1G, 2G,4G,8G,16G. If the pharmacist can combine these weights to create new weights, how many different weights are possible?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A pharmacist uses 5 seperate weights. 1G, 2G,4G,8G,16G. If the pharmacist can combine these weights to create new weights, how many different weights are possible?
-----------------
32, if you count zero. 31 if not.
--------------
The weights are:
%282%5E0%29+to+%282%5E4%29
The possible combinations are any number in binary from 0 to 31 grams.