Question 249758: Question: Find three consecutive odd integers such that twice the first added to three times the second is equal to 83. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! 2n+1
2n+3
2n+5
2(2n+1)+3(2n+3)=83
This is rather curious since the third integer is not mentioned.
I tried this with n+1, n+3 and n+5
2(n+1)+3(n+3)=83
and there are no integer solutions.
Something is wrong or missing.