SOLUTION: A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 36t + 9.
a. In how many seconds
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 36t + 9.
a. In how many seconds
Log On
Question 249718: A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 36t + 9.
a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary.
b. What is the ball's maximum height? Answer by solver91311(24713) (Show Source):
The graph of the height function is a parabola, opening down because of the negative lead coefficient. The questions asked are nothing more than the coordinates of the vertex of the parabola.
The -coordinate of the vertex of a parabola described by an equation in the form:
is given by
Just plug in your numbers and calculate.
For the second part of your problem, simply calculate