SOLUTION: The length of a rectangle is 2in longer than its width. If the perimeter of the rectangle is 36in , find its area.

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Question 249558: The length of a rectangle is 2in longer than its width. If the perimeter of the rectangle is 36in , find its area.
Found 2 solutions by Nikki456, richwmiller:
Answer by Nikki456(9) About Me  (Show Source):
You can put this solution on YOUR website!
You could solve this by using the area and perimeter formula. The formula for perimeter is 2L+2W. So you could make an equation:
2L+2W=P
substitute:
2(W+2)+2W=36
distribute: 2W+4+2W=36
4W+4=36
subtract 4 on both sides:
4W=32
divide by 4 on both sides:
W=8
Now plug this back into the original equation: 2L+2W=36
2L+2(8)=36
2L+16=36
2L=20
L=10
The length is 10 in. and the width is 8 in. You could use a formula to find the area. The formula is LxW=A
So 10x8 is 80
Your final answer is 80+in%5E2.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+2
36=2L+2W
36=2(W+2)+2W
36=2W+4+2W
32=4W
8=W
L=10
check
2w+2L=20+16=36
ok
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