SOLUTION: The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd , find its area.
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Question 249430
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The length of a rectangle is twice its width. If the perimeter of the rectangle is 48 yd , find its area.
Answer by
checkley77(12844)
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L=2W
2L+2W=P
2(2W)+2W=48
4W+2W=48
6W=48
W=48/6
W=8 YDS. FOR THE WIDTH.
L=2*8=16 YDS. FOR THE LENGTH.
PROOF:
2*16+2*8=48
32+16=48
48=48