SOLUTION: I'm having difficulty figuring out the equation for this word problem from our variable equation unit: A truck leaves a rest stop traveling at a steady rate of 56 mph. A car

Algebra ->  Equations -> SOLUTION: I'm having difficulty figuring out the equation for this word problem from our variable equation unit: A truck leaves a rest stop traveling at a steady rate of 56 mph. A car       Log On


   

Question 24943: I'm having difficulty figuring out the equation for this word problem from our variable equation unit:
A truck leaves a rest stop traveling at a steady rate of 56 mph. A car leaves the same rest stop 1/4 hour later, following the truck at a steady rate of 64mph. How long after the truck leaves the rest stop, will the car overtake the truck? Thank you!
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
First your can simplify 1/4 - 0.25h
Truck's peed = 56mph
Cars' speed = 64mph
After 1/4 hour later with the truck = 56(x+0.25)
In where x is the distance.
Car's distance = 64x

56(x+0.25)=64x
56x+14=64x
simplify
8x=14
8x%2F8=14%2F8
x=1.75

hence it will take the truck 1.75hour to cross the car
Paul.