SOLUTION: The height of an object thrown in the air is given by h = -1.6t2 + 8t + 2, where h is in feet and t is the time in seconds the object has been in motion. At what time (to the near
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Question 249361: The height of an object thrown in the air is given by h = -1.6t2 + 8t + 2, where h is in feet and t is the time in seconds the object has been in motion. At what time (to the nearest tenth) is the object 10 feet in the air? Answer by richwmiller(17219) (Show Source):
