SOLUTION: Hello, Can someone help me with these, I have some of the graphs but I not able to post them to this screen, and the last two problem I stuck on them since yesterday. Please help

Algebra ->  Exponents -> SOLUTION: Hello, Can someone help me with these, I have some of the graphs but I not able to post them to this screen, and the last two problem I stuck on them since yesterday. Please help       Log On


   

Question 249192: Hello,
Can someone help me with these, I have some of the graphs but I not able to post them to this screen, and the last two problem I stuck on them since yesterday. Please help me

1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Use the resulting pairs to plot the graph. State the equation of the line asymptotic to the graph. .y=5%5Ex%2B3
I have a graph but I not sure that it is right and it will not post to this screen.
2. evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Use the resulting ordered pairs to plot the graph. State the equation of the line asymptotic to the graph. Y=+-log5%5Ex
Again I have the graph but I not sure if it is right and I can not post it to this screen

3. solve; the number of dislocated impulses per cubic inch in a transformer increases when lightning strikes by D=1900(2)^x, where x is the time in milliseconds fo the lightning strike. Find the number of dislocated impulses at x=0 and x=4


4. how long will it take for the population of a certain country to triple if its annual growth rate is 2.8%?(round to the nearest year). Use the exponential growth model P(t)=P0e^kt
Thank you,
Tammy
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first two to get you started.

# 1

In order to graph y=5%5Ex%2B3, we need to plot a few points.


To get points in the form of (x,y), we need to find corresponding 'y' values to given 'x' values.


Let's find the y value when x=-3 note: you can start at any x value.


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%28-3%29%2B3 Plug in x=-3.


y=0.008%2B3 Raise 5 to the power of -3 to get 0.008.


y=3.008 Add.


So if x=-3, then y=3.008 which gives us the point (-3,3.008).


----------------------------


Let's find the y value when x=-2


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%28-2%29%2B3 Plug in x=-2.


y=0.04%2B3 Raise 5 to the power of -2 to get 0.04.


y=3.04 Add.


So if x=-2, then y=3.04 which gives us the point (-2,3.04).


----------------------------


Let's find the y value when x=-1


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%28-1%29%2B3 Plug in x=-1.


y=0.2%2B3 Raise 5 to the power of -1 to get 0.2.


y=3.2 Add.


So if x=-1, then y=3.2 which gives us the point (-1,3.2).


----------------------------


Let's find the y value when x=1


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%281%29%2B3 Plug in x=1.


y=5%2B3 Raise 5 to the power of 1 to get 5.


y=8 Add.


So if x=1, then y=8 which gives us the point (1,8).


----------------------------


Let's find the y value when x=2


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%282%29%2B3 Plug in x=2.


y=25%2B3 Raise 5 to the power of 2 to get 25.


y=28 Add.


So if x=2, then y=28 which gives us the point (2,28).


----------------------------


Let's find the y value when x=3


y=5%5Ex%2B3 Start with the given equation.


y=5%5E%283%29%2B3 Plug in x=3.


y=125%2B3 Raise 5 to the power of 3 to get 125.


y=128 Add.


So if x=3, then y=128 which gives us the point (3,128).


----------------------------


Now let's make a table of the values we just found.


Table of Values:





xy
-33.008


-23.04


-13.2


18


228


3128

Now let's plot the points. Note: not all of the points will be visible.




Graph:


Now draw a curve through all of the points to graph y=5%5Ex%2B3:


Graph of y=5%5Ex%2B3

============================================================
# 2


In order to graph y=-log%285%2C%28x%29%29, we need to plot a few points.


To get points in the form of (x,y), we need to find corresponding 'y' values to given 'x' values.


Let's find the y value when x=0.25


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%280.25%29%29 Plug in x=0.25.


y=-%28-0.861%29 Evaluate the log base 5 of 0.25 to get -0.861.


y=0.861 Negate -0.861 to get 0.861.


So if x=0.25, then y=0.861 which gives us the point (0.25,0.861).


----------------------------


Let's find the y value when x=0.5


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%280.5%29%29 Plug in x=0.5.


y=-%28-0.431%29 Evaluate the log base 5 of 0.5 to get -0.431.


y=0.431 Negate -0.431 to get 0.431.


So if x=0.5, then y=0.431 which gives us the point (0.5,0.431).


----------------------------


Let's find the y value when x=0.75


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%280.75%29%29 Plug in x=0.75.


y=-%28-0.179%29 Evaluate the log base 5 of 0.75 to get -0.179.


y=0.179 Negate -0.179 to get 0.179.


So if x=0.75, then y=0.179 which gives us the point (0.75,0.179).


----------------------------


Let's find the y value when x=1


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%281%29%29 Plug in x=1.


y=-0 Evaluate the log base 5 of 1 to get 0.


So if x=1, then y=0 which gives us the point (1,0).


----------------------------


Let's find the y value when x=2


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%282%29%29 Plug in x=2.


y=-0.431 Evaluate the log base 5 of 2 to get 0.431.


So if x=2, then y=-0.431 which gives us the point (2,-0.431).


----------------------------


Let's find the y value when x=3


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%283%29%29 Plug in x=3.


y=-0.683 Evaluate the log base 5 of 3 to get 0.683.


So if x=3, then y=-0.683 which gives us the point (3,-0.683).


----------------------------


Let's find the y value when x=4


y=-log%285%2C%28x%29%29 Start with the given equation.


y=-log%285%2C%284%29%29 Plug in x=4.


y=-0.861 Evaluate the log base 5 of 4 to get 0.861.


So if x=4, then y=-0.861 which gives us the point (4,-0.861).


----------------------------


Now let's make a table of the values we just found.


Table of Values:





xy
0.250.861


0.50.431


0.750.179


10


2-0.431


3-0.683


4-0.861

Now let's plot the points:




Graph:


Now draw a curve through all of the points to graph y=-log%285%2C%28x%29%29:


Graph of y=-log%285%2C%28x%29%29