SOLUTION: Here's my problem: Two friends live 15 miles apart. One day, they decided to jog and meet each other. Tanya leaves her house and heads east, jogging at a rate of 2.5 miles per

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Here's my problem: Two friends live 15 miles apart. One day, they decided to jog and meet each other. Tanya leaves her house and heads east, jogging at a rate of 2.5 miles per      Log On


   

Question 248927: Here's my problem:
Two friends live 15 miles apart. One day, they decided to jog and meet each other. Tanya leaves her house and heads east, jogging at a rate of 2.5 miles per hour. At the same time Kelly leaves her house and heads west, jogging at a rate of 3.5 miles per hour. How long does it take for the two to meet?
Thank you.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
rt=d
rt+rt=d
times will be the same
2.5t+3.5t=15
t(6)=15
t=15/6=5/3=1 2/3 =1 hr 40 minutes