SOLUTION: bill & jose's discount cinema sold adults' tickets for $4.10 each and children's tickets for $2.70 each. last tuesday, a total of $331.30 was collected from 89 movie watchers. how
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-> SOLUTION: bill & jose's discount cinema sold adults' tickets for $4.10 each and children's tickets for $2.70 each. last tuesday, a total of $331.30 was collected from 89 movie watchers. how
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Question 248836: bill & jose's discount cinema sold adults' tickets for $4.10 each and children's tickets for $2.70 each. last tuesday, a total of $331.30 was collected from 89 movie watchers. how many of each type of ticket were sold? (let x represent the number of adults' tickets and y represent the number of children's tickets.)
4. solve by applying the quadratic formula. show your work. 3x2 - 2x + 3 = 0. Found 2 solutions by josmiceli, tutorcecilia:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = number of adult tickets sold
Let = number of children's tickets sold
given: (in cents)
(1)
(2)
Multiply both sides of (2) by
and subtract from (1)
(1)
(2)
and, since
65 adult tickets and 24 children's tickets were sold
check:
(1)
OK
You can put this solution on YOUR website! Use: x+y=total items
So, x+y=89
y=89-x
and
Use: ax+by=(total)(ratio)
So, 4.10x+2.70y=331.30
4.10x+2.70(89-x)=331.30[substitute y=89-x)
4.10x+240.30-2.70x=331.30
4.10x-2.70x=331.30-240.30
1.40x=91
x=91/1.40
x=65 adult tickes
65+y=89
so,
y=89-65=24 children tickets sold